A mass m starting from A reaches B of a frictionless track. On reaching A it pushes the track with a force equal to x times its weight, then applicable relation is
A
h = 
B
h = 
C
h = r
D
h = 
Text Solution
Verified by ExpertsThe correct answer is:
A
K.E. of block at B = P.E. at A – P.E. at B
i.e., 
mv 2 = mgh – mg 2 r = mg (h – 2r)
i.e., v 2 = 2g (h – 2r) ………. (i)
Also 
- mg = x mg
or v 2 = (x +1) rg ………... (ii)
Equating (i) and (ii)
2g (h – 2r) = (x +1) gr
or 2gh = (x + 1) gr + 4gr
= (x + 5) gr
or h = 
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